KCTF 2023 第八题 AI核心地带_游戏逆向|游戏安全|yxfzedu.com

输入范围是数字

COUNT & 1 == 1时，计算结果相加为 mod 10

COUNT & 1 != 1时，计算结果相加不为 mod 10，有其他校验

观察到401283，edi != 9 时为正确输入

修改程序爆破

       def 
       CCC(i):
      

           
       if
       (i & 
       1
       ):
      

               
       num 
       = 
       (
       52 
       - 
       (
       0xFFFEC610 
       >> (i 
       % 
       0x1F
       ))) 
       % 
       10
      

           
       else
       :
      

               
       num 
       = 
       (
       52 
       - 
       (
       0xFFFEC610 
       >> (i 
       % 
       0x1F
       ))) 
       % 
       10
      

           
       return 
       num
      

        
      

       import 
       subprocess
      

       import 
       os
      

       F 
       = 
       ""
      

       for 
       L 
       in 
       range
       (
       1000
       ):
      

           
       tempF 
       = 
       F
      

           
       print
       (tempF)
      

           
       num 
       = 
       CCC(L)
      

           
       if
       (L&
       1
       ):
      

               
       F 
       +
       = 
       chr
       (
       48
       +
       num)
      

               
       s 
       = 
       subprocess.Popen(
       "Z.exe"
       ,stdout
       =
       subprocess.PIPE, stdin
       =
       subprocess.PIPE, shell
       =
       True
       )
      

               
       s.stdin.write((F).encode()
       +
       b
       "\n"
       )
      

               
       s.stdin.close()
      

               
       out 
       = 
       s.stdout.read()
      

               
       if
       (b
       'OK' 
       in 
       out):
      

                   
       print
       (
       "ACCEPTED"
       ,F)
      

                   
       exit(
       0
       )
      

               
       continue
      

           
       else
       :
      

               
       T
       =
       -
       1
      

               
       for 
       i 
       in 
       range
       (
       0
       ,
       10
       ):
      

                   
       if
       (i 
       =
       = 
       num):
      

                       
       continue
      

                   
       s 
       = 
       subprocess.Popen(
       "Z.exe"
       ,stdout
       =
       subprocess.PIPE, stdin
       =
       subprocess.PIPE, shell
       =
       True
       )
      

                   
       s.stdin.write((tempF
       +
       chr
       (
       48
       +
       i)).encode()
       +
       b
       "\n"
       )
      

                   
       s.stdin.close()
      

                   
       out 
       = 
       s.stdout.read()
      

                   
       s.stdout.close()
      

                   
       if
       (b
       'OK' 
       in 
       out):
      

                       
       F 
       +
       = 
       chr
       (
       48
       +
       i)
      

                       
       print
       (
       "ACCEPTED"
       ,F)
      

                       
       exit(
       0
       )
      

                   
       if
       (b
       'FAIL' 
       in 
       out):
      

                       
       F 
       +
       = 
       chr
       (
       48
       +
       i)
      

                       
       T
       =
       i
      

                       
       break
      

               
       if
       (T
       =
       =
       -
       1
       ):
      

                   
       print
       (
       "Error"
       )
      

得到一个非常长的答案

582606981190746395118531851185249089744027265368693769576937697816165851808443150195011501950410798490871663488927792799277958360668112074539521851185318514909974002766535869476937695769681626582180144305010501950115040079949037162348792789277927995826067811907483951185218511853490897410272653986937694769376988161658318084433501950105019504207984904716634829277927892779584606681100745395418511852185149009740027365358697769376947696816365821809443050125019501050400790490371673487927

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KCTF 2023 第八题 AI核心地带

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